Question

(04.02 mc)
what is the solution to the following system of equations?
4x + 2y = 6
x - y = 3

○ (2, 1)
○ (-2, -1)
○ (2, 4)
○ (2, -1)

Explanation:

Step1: Solve the second equation for x

From \( x - y = 3 \), we can express \( x \) as \( x = y + 3 \).

Step2: Substitute x into the first equation

Substitute \( x = y + 3 \) into \( 4x + 2y = 6 \):

$$
LATEXBLOCK0
$$

Step3: Find x using y = -1

Substitute \( y = -1 \) into \( x = y + 3 \):
\( x = -1 + 3 = 2 \)
So the solution is \( (2, -1) \).

Answer:

(2, -1)