Geometrie
Dreiecke, Kreise, Koordinatengeometrie und Beweisaufgaben.
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3. pour dessiner le plan dune ferme de toit, on trace dabord un segment…
Les triangles \( ABD \) et \( CBD \) sont isométriques (congruents) car : - \( AD = DC \) ( \( D \) est le milieu de \( AC \) ), - \( \angle ADB = \angle CDB = 90^\circ \) ( \( DB…
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similar figures in exercises 1–8, the figures are similar. find each mi…
1. $18$ m 2. $27$ in 3. $36$ km 4. $4$ ft 5. $16$ in 6. $15$ m 7. $31.5$ m 8. $78.75$ yd 9. $9$ feet 10. $30$ inches 11. $\frac{1}{4}$ yard
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practice with linear pairs and vertical angles. which angles are linear…
# Explanation: To determine linear pairs, we use the definition: a linear pair of angles are adjacent angles that form a straight line (sum to \(180^\circ\)) and share a common si…
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finding unknown angle measures what are the numerical measures of each …
∠1 and ∠3 measure \(\boldsymbol{29}\) degrees. ∠2 and ∠4 measure \(\boldsymbol{151}\) degrees. (Note: The filled answers in the problem might be incorrect; the correct calculation…
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4. the point on the graph that lies on the y - axis (vertical axis) is …
The y - intercept tells you the runner's starting position (distance from a reference, e.g., the starting line) at the start of the run (when time \( t = 0 \)). ### Question 5A
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find the missing side length. assume that all intersecting sides meet a…
11 ft
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type the correct answer in each box. spell all words correctly. complet…
If one triangle can be mapped to another triangle by a series of rigid transformations, then the triangles are called **congruent** and the corresponding **sides** and angles are …
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mathematics diagnostic assessment given: ( ab cong dc ) and ( bc cong a…
C. side-side-side congruence
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4. name the rule that applies to this shape.
The shape is a rhombus (or a quadrilateral with all sides equal). The rule that applies is: In a rhombus (a quadrilateral with all four sides of equal length), opposite sides are …
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14 select the correct answer from the drop - down menu. what is the rul…
the absolute value of the difference
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by which angle must (overline{ab}) turn about point (a) in the clockwis…
B. 180°
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find the smallest angle of $\\triangle wxy$. assume that $c$ is a posit…
The smallest angle is \(\angle X\) (opposite the shortest side \(44c\)).
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congruent supplements theorem linear pair theorem given definition of s…
1. $m\angle1 = 110^\circ$ and $m\angle2 = 70^\circ$: $\boldsymbol{given}$ 2. $\angle1$ is supplementary to $\angle2$: $\boldsymbol{definition\ of\ supplementary\ angles}$ 3. $\ang…
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type the correct answer in the box. use numerals instead of words. if n…
8
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10) $y \\geq x + 4$
To graph \( y\geq x + 4 \): 1. Draw the line \( y=x + 4 \) as a solid line (because of the "greater than or equal to" symbol). The line has a slope of 1 and a y - intercept at \( …
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12) x + 3y < 15
To graph \(x + 3y<15\): 1. Rewrite as \(y<-\frac{1}{3}x + 5\). 2. Draw a dashed line \(y=-\frac{1}{3}x + 5\) (passing through \((0,5)\) and \((3,4)\) etc.). 3. Shade the region be…
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10. eng kichik yuz olchov birligiga otkazib hisoblang. 42 dm² 26 cm² - …
1. $4066\ \text{cm}^2$ 2. $1200\ \text{mm}^2$ 3. $92100\ \text{cm}^2$
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pythagorean theorem © 2013 kuta software llc. all rights reserved. find…
\( \sqrt{209} \) ft ### Problem 2: Find the missing side (right triangle, legs \( 5\sqrt{2} \) mi, 7 mi, hypotenuse \( x \))
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name: class: polygon/ quadrilateral quiz 1. write the equation used to …
The equation used to solve for the sum of the interior angles of a polygon is \( S=(n - 2)\times180^\circ \) (where \( S \) represents the sum of interior angles and \( n \) repre…
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goes through points (-2, -1) and (-3, 5) y = -1/6x + 1 y = -6x - 13 y =…
\( y = - 6x-13 \) (corresponding to the blue option: \( y = - 6x - 13 \))
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geometry name date period unit 5 review directions: complete the follow…
1. opposite 2. hypotenuse 3. adjacent 4. right 5. right 6. right angle 7. 17 ft 8. 2 cm 9. The hypotenuse is the longest side of the right triangle, opposite the 90° (right) angle…
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6. find the distance between the two points. use graph paper if necessa…
7.6
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5. find the missing side length. round to the nearest tenth. 14 6
12.6
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4. find the missing side length. round to the nearest tenth.
10.4
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f(x) = -3x² g(x) = -5x³ - 2x⁴ + 1 h(x) = 2 + 5x 1. add polynomials. f(x…
\( -2x^4 - 5x^3 - 3x^2 + 1 \) ### 2. Subtract polynomials \( f(x) - h(x) \)
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graph each equation. 9) \\(\\frac{x^2}{4} + \\frac{y^2}{9} = 1\\)
The graph is an ellipse centered at the origin with vertices at \((0,3)\), \((0, - 3)\) and co - vertices at \((2,0)\), \((- 2,0)\), drawn by plotting these points and sketching a…
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graph each equation. 9) \\(\\dfrac{x^2}{4} + \\dfrac{y^2}{9} = 1\\)
The graph is an ellipse centered at the origin $(0,0)$ with vertices at $(0, 3)$, $(0, -3)$ and co-vertices at $(2, 0)$, $(-2, 0)$, forming a vertical elongated oval shape passing…
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graph each equation. 9) \\(\\dfrac{x^2}{4} + \\dfrac{y^2}{9} = 1\\)
The graph is an ellipse with vertices at $(0, 3)$, $(0, -3)$ and co-vertices at $(2, 0)$, $(-2, 0)$, forming a vertical-oriented ellipse centered at the origin $(0,0)$.
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graph each equation. 9) \\(\\dfrac{x^2}{4} + \\dfrac{y^2}{9} = 1\\)
The graph is an ellipse with vertices at $(0, 3)$, $(0, -3)$ and co-vertices at $(2, 0)$, $(-2, 0)$, forming a vertical elongated oval shape centered at the origin $(0,0)$.
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graph each equation. 9) \\(\frac{x^2}{4} + \frac{y^2}{9} = 1\\)
The graph is an ellipse centered at the origin $(0,0)$ with vertices at $(0, 3)$, $(0, -3)$ and co-vertices at $(2, 0)$, $(-2, 0)$, forming a vertical elongated oval shape passing…
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find the length of the unknown sides f round all answers to 2 decimal p…
The length of the unknown side \(c\) is approximately \(3.61\space cm\)
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find the length of the unknown sides f round all answers to 2 decimal p…
# Explanation: ## Step1: Identify the formula This is a right - triangle, so we can use the Pythagorean theorem. The Pythagorean theorem states that for a right[SSE onError error]
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graph $y = \\frac{4}{5}x - 7$.
To graph \( y=\frac{4}{5}x - 7 \): 1. Plot the y - intercept \( (0,-7) \). 2. Use the slope \( \frac{4}{5} \) to find another point: from \( (0,-7) \), move up 4 units and right 5…
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graph each equation. 9) \\(\\frac{x^2}{4} + \\frac{y^2}{9} = 1\\)
The graph is an ellipse centered at the origin \((0,0)\) with vertices at \((0, 3)\), \((0,-3)\) and co - vertices at \((2,0)\), \((-2,0)\). To graph it, plot these four points an…
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graph each equation. 9) \\(\\frac{x^2}{4} + \\frac{y^2}{9} = 1\\)
The graph is an ellipse centered at the origin with vertices at \((0, 3)\), \((0,-3)\) and co - vertices at \((2,0)\), \((-2,0)\), drawn through these points. (To actually graph i…
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graph each equation. 9) \\(\\dfrac{x^2}{4} + \\dfrac{y^2}{9} = 1\\) coo…
The graph is an ellipse centered at the origin $(0,0)$ with vertices at $(0, 3)$, $(0, -3)$ and co-vertices at $(2, 0)$, $(-2, 0)$, forming a vertical elongated oval shape passing…
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graph each equation. 9) \\(\\dfrac{x^2}{4} + \\dfrac{y^2}{9} = 1\\)
The graph is an ellipse centered at the origin $(0,0)$ with vertices at $(2,0)$, $(-2,0)$, $(0,3)$, and $(0,-3)$, connected by a smooth, oval-shaped curve.
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graph each equation. 9) \\(\\dfrac{x^2}{4} + \\dfrac{y^2}{9} = 1\\) coo…
The graph is an ellipse centered at the origin $(0,0)$ with vertices at $(0, 3)$, $(0, -3)$ and co-vertices at $(2, 0)$, $(-2, 0)$, forming a vertical elongated oval shape passing…
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graph each equation. 9) \\(\\dfrac{x^2}{4} + \\dfrac{y^2}{9} = 1\\)
The graph is an ellipse centered at the origin $(0,0)$ with vertices at $(0, 3)$, $(0, -3)$ and co-vertices at $(2, 0)$, $(-2, 0)$, forming a vertical elongated oval shape passing…
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graph each equation. 9) \\(\\dfrac{x^2}{4} + \\dfrac{y^2}{9} = 1\\) coo…
This is an ellipse with vertices at $(0, 3)$, $(0, -3)$ and co-vertices at $(2, 0)$, $(-2, 0)$, centered at the origin, plotted on the given grid.
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graph each equation. 9) \\(\\dfrac{x^2}{4} + \\dfrac{y^2}{9} = 1\\)
This is an ellipse with vertices at $(0, 3)$, $(0, -3)$ and co-vertices at $(2, 0)$, $(-2, 0)$, centered at the origin.
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graph each equation. 9) \\(\\dfrac{x^2}{4} + \\dfrac{y^2}{9} = 1\\)
1. Plot the vertices at $(0, 3)$ and $(0, -3)$, and co-vertices at $(2, 0)$ and $(-2, 0)$ on the provided coordinate grid. 2. Draw a smooth, symmetric ellipse passing through all …
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1. given ( lm = 30 ), ( mn = 40 ), ( ln = 50 ), ( pq = 15 ), ( qr = 20 …
1. **Statement 1**: \( LM = 30 \), \( MN = 40 \), \( LN = 50 \), \( PQ = 15 \), \( QR = 20 \), \( PR = 25 \) 2. **Reason for Statement 2**: To check for SSS similarity, set up rat…
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10. use the law of syllogism to write a new conditional statement that …
If a triangle has three equal angles, then the triangle has three equal sides
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8. consider the statement \if a triangle has three equal sides, then it…
### For Question 8: The hypothesis is: a triangle has three equal sides The conclusion is: it is an equilateral triangle ### For Question 9: Condition statement: If a shape is a t…
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6. write the property that justifies each step. solve $4x - 10 = 5x + 1…
Justifications (in order): Given equation, Subtraction Property of Equality, Addition Property of Equality, Division Property of Equality; $x=-27$ --- ### Problem 7
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graph each equation. 9) \\(\\dfrac{x^2}{4} + \\dfrac{y^2}{9} = 1\\)
The graph is an ellipse centered at the origin $(0,0)$ with vertices at $(0, 3)$, $(0, -3)$ and co-vertices at $(2, 0)$, $(-2, 0)$, forming a vertical elongated oval shape passing…
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graph each equation. 9) \\(\\frac{x^2}{4} + \\frac{y^2}{9} = 1\\)
The graph is an ellipse centered at the origin $(0,0)$ with vertices at $(0, 3)$, $(0, -3)$ and co-vertices at $(2, 0)$, $(-2, 0)$, forming a vertical elongated oval shape passing…
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graph each equation. 9) \\(\\dfrac{x^2}{4} + \\dfrac{y^2}{9} = 1\\)
The graph is an ellipse centered at the origin $(0,0)$ with vertices at $(0, 3)$, $(0, -3)$ and co-vertices at $(2, 0)$, $(-2, 0)$, forming a vertical elongated oval shape passing…
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graph each equation. 9) \\(\\dfrac{x^2}{4} + \\dfrac{y^2}{9} = 1\\)
The graph is an ellipse centered at the origin $(0,0)$ with vertices at $(0, 3)$, $(0, -3)$ and co-vertices at $(2, 0)$, $(-2, 0)$, forming a vertical elongated oval shape passing…
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graph each equation. 9) \\(\\dfrac{x^2}{4} + \\dfrac{y^2}{9} = 1\\)
1. Plot the points $(0, 3)$, $(0, -3)$, $(2, 0)$, and $(-2, 0)$ on the coordinate grid. 2. Draw a smooth, symmetric oval (ellipse) that passes through all four points, with its lo…
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graph each equation. 9) \\(\\dfrac{x^2}{4} + \\dfrac{y^2}{9} = 1\\)
The graph is an ellipse centered at the origin $(0,0)$ with vertices at $(0, 3)$, $(0, -3)$ and co-vertices at $(2, 0)$, $(-2, 0)$, forming a vertical elongated oval shape passing…
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5 figurën e dhënë e zhvendosim paralelisht në drejtimin e përcaktuar me…
Coordinates of translated vertices: $A'(2, 3)$ $B'(2, -1)$ $C'(8, -6)$ $D'(8, -2)$ (To complete the figure, plot these points and connect them in order $A'\to B'\to C'\to D'\to A'…
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graph each equation. 9) \\(\frac{x^2}{4} + \frac{y^2}{9} = 1\\)
The graph is an ellipse centered at the origin $(0,0)$ with vertices at $(0, 3)$, $(0, -3)$ and co-vertices at $(2, 0)$, $(-2, 0)$, forming a vertical elongated oval shape passing…
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graph each equation. 9) \\(\\dfrac{x^2}{4} + \\dfrac{y^2}{9} = 1\\)
The ellipse has vertices at $(0, 3)$, $(0, -3)$ and co-vertices at $(2, 0)$, $(-2, 0)$. A smooth, closed curve connecting these points is the graph of $\frac{x^2}{4} + \frac{y^2}{…
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graph each equation. 9) \\(\frac{x^2}{4} + \frac{y^2}{9} = 1\\)
The graph is an ellipse centered at the origin $(0,0)$ with vertices at $(0, 3)$, $(0, -3)$ and co-vertices at $(2, 0)$, $(-2, 0)$, forming a vertical elongated oval shape passing…
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graph each equation. 9) \\(\\frac{x^2}{4} + \\frac{y^2}{9} = 1\\)
The graph is an ellipse centered at the origin $(0,0)$ with vertices at $(0, 3)$, $(0, -3)$ and co-vertices at $(2, 0)$, $(-2, 0)$, forming a vertical elongated oval shape passing…
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shkruajmë koordinatat e kulmeve të figurës së dhënë. e zhvendosim atë p…
Original coordinates: $B(2, 3)$, $C(3, 3)$, $D(3, 4)$, $E(4, 4)$, $F(4, 2)$, $G(3, 2)$, $H(3, 6)$ Translated coordinates: $B'(2, -2)$, $C'(3, -2)$, $D'(3, -1)$, $E'(4, -1)$, $F'(4…
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evaluate independent practice lesson 9.2 homework complete problems 5, …
1. Problem 5: Pattern: Backward alphabetical order. Next two letters: U, T 2. Problem 7: Pattern: Shapes increase by 1 side each. Next two shapes: A hexagon (6 sides), a heptagon …
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teacher voice - as long as the conclusion of one conditional statement …
4) If it is raining today, then you can go to the mall after school. 5) You cannot use the Law of Syllogism to write a new conditional statement.
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graph $y = \\frac{4}{5}x - 7$.
The graph of \( y = \frac{4}{5}x-7 \) has a y - intercept at \( (0, - 7) \) and a slope of \( \frac{4}{5} \). Two points on the line can be \( (0,-7) \) and \( (5,-3) \), and a st…
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graph each equation. 9) \\(\\frac{x^2}{4} + \\frac{y^2}{9} = 1\\)
To graph \(\frac{x^{2}}{4}+\frac{y^{2}}{9}=1\): 1. Recognize it as an ellipse with major axis along the \(y\)-axis, \(a = 3\), \(b = 2\). 2. Plot vertices \((0,3)\), \((0, - 3)\) …
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graph each equation. 9) \\(\\frac{x^2}{4} + \\frac{y^2}{9} = 1\\)
To graph \(\frac{x^{2}}{4}+\frac{y^{2}}{9}=1\): 1. Recognize it as a vertical ellipse centered at \((0,0)\) with \(a = 3\) (along \(y\) - axis) and \(b = 2\) (along \(x\) - axis).…
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graph each equation. 9) \\(\\frac{x^2}{4} + \\frac{y^2}{9} = 1\\)
To graph \(\frac{x^{2}}{4}+\frac{y^{2}}{9}=1\) (an ellipse): 1. Identify it as an ellipse with vertical major axis (since \(a^{2}=9\) and \(b^{2}=4\), \(a > b\)), centered at \((0…
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graph each equation. 9) \\(\\frac{x^2}{4} + \\frac{y^2}{9} = 1\\)
The graph is an ellipse centered at the origin with vertices at \((0, \pm3)\) and co - vertices at \((\pm2, 0)\). To draw it, plot the points \((0,3)\), \((0, - 3)\), \((2,0)\), \…
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graph each equation. 9) \\(dfrac{x^2}{4} + dfrac{y^2}{9} = 1\\)
The graph is an ellipse centered at the origin \((0,0)\) with vertices at \((0, 3)\), \((0,-3)\) and co - vertices at \((2,0)\), \((-2,0)\). The ellipse is drawn by connecting the…
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graph each equation. 9) \\(\\dfrac{x^2}{4} + \\dfrac{y^2}{9} = 1\\)
The graph is an ellipse centered at the origin \((0,0)\) with vertices at \((0, 3)\), \((0,-3)\) and co - vertices at \((2,0)\), \((-2,0)\), and the ellipse is drawn passing throu…
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graph each equation. 9) \\(\\frac{x^2}{4} + \\frac{y^2}{9} = 1\\)
The graph is an ellipse with vertices at \((0,\pm3)\) and co - vertices at \((\pm2,0)\), symmetric about the \(x\) and \(y\) axes, passing through the points \((0,3)\), \((0, - 3)…
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graph each equation. 9) \\(\\frac{x^2}{4} + \\frac{y^2}{9} = 1\\)
To graph \(\frac{x^{2}}{4}+\frac{y^{2}}{9}=1\): 1. Recognize it as an ellipse centered at \((0,0)\) with major axis along the \(y\)-axis, \(a = 3\), \(b = 2\). 2. Plot the vertice…
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graph each equation. 9) \\(\\frac{x^2}{4} + \\frac{y^2}{9} = 1\\)
The graph is an ellipse with vertices at \((0,\pm3)\) and co - vertices at \((\pm2,0)\), plotted and connected as described above. (The actual graph is an ellipse centered at the …
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removed from one arm, so each star has one more unshaded arm than in th…
To sketch the fifth figure: 1. Draw a horizontal row of 5 connected squares (the base). 2. Draw a vertical column of 5 connected squares, where the bottom square of the column is …
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graph each equation. 9) \\(\\dfrac{x^2}{4} + \\dfrac{y^2}{9} = 1\\)
To graph \(\frac{x^2}{4}+\frac{y^2}{9}=1\): 1. Recognize it as a vertical ellipse with center \((0,0)\). 2. Plot vertices \((0, 3)\), \((0, - 3)\) and co - vertices \((2,0)\), \((…
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graph each equation. 9) \\(\frac{x^2}{4} + \frac{y^2}{9} = 1\\)
The graph is an ellipse with vertical vertices at $(0, 3)$ and $(0, -3)$, horizontal co-vertices at $(2, 0)$ and $(-2, 0)$, forming a smooth, symmetric oval centered at the origin…
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graph each equation. 9) \\(\\frac{x^2}{4} + \\frac{y^2}{9} = 1\\)
The graph is an ellipse centered at the origin $(0,0)$ with vertices at $(0, 3)$, $(0, -3)$ and co-vertices at $(2, 0)$, $(-2, 0)$, forming a vertical elongated oval shape passing…
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graph each equation. 9) \\(\\frac{x^2}{4} + \\frac{y^2}{9} = 1\\)
The graph is an ellipse centered at the origin $(0,0)$ with vertices at $(0, 3)$, $(0, -3)$ and co-vertices at $(2, 0)$, $(-2, 0)$, forming a vertical elongated oval passing throu…
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graph each equation. 9) \\(\\frac{x^2}{4} + \\frac{y^2}{9} = 1\\)
The graph is an ellipse centered at the origin $(0,0)$, with vertices at $(2, 0)$, $(-2, 0)$, $(0, 3)$, and $(0, -3)$, forming a vertical elongated oval shape passing through thes…
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graph $y = \\frac{4}{5}x - 7$.
The graph is a straight line passing through the points $(0, -7)$ and $(5, -3)$, following the equation $y=\frac{4}{5}x-7$.
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retrieval solve each proportion. show your work and check your solution…
1. $x = 8$ 2. $b = 42$ 3. $x = 10$ 4. Three equivalent ratios: $\frac{2}{4}$, $\frac{3}{6}$, $\frac{x}{5}$ (all simplify to $\frac{1}{2}$)
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graph each equation. 9) \\(\\frac{x^2}{4} + \\frac{y^2}{9} = 1\\)
The graph is a vertical ellipse centered at the origin, passing through the points $(2,0)$, $(-2,0)$, $(0,3)$, and $(0,-3)$, with a smooth curve connecting these points.
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graph each equation. 9) \\(\\frac{x^2}{4} + \\frac{y^2}{9} = 1\\)
The graph is an ellipse centered at the origin with vertices at $(0, 3)$, $(0, -3)$ and co-vertices at $(2, 0)$, $(-2, 0)$, forming a vertical elongated oval shape passing through…
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graph each equation. 9) \\(\\frac{x^2}{4} + \\frac{y^2}{9} = 1\\)
The graph is an ellipse centered at the origin $(0,0)$ with vertices at $(2, 0)$, $(-2, 0)$, $(0, 3)$, and $(0, -3)$, forming a vertical elongated oval shape passing through these…
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graph each equation. 9) \\(\\frac{x^2}{4} + \\frac{y^2}{9} = 1\\)
The graph is a vertical ellipse with vertices at $(0, 3)$, $(0, -3)$ and co-vertices at $(2, 0)$, $(-2, 0)$, drawn as a smooth closed curve through these points on the provided co…
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graph each equation. 9) \\(\\frac{x^2}{4} + \\frac{y^2}{9} = 1\\)
The graph is an ellipse with vertices at $(0, 3)$, $(0, -3)$ and co-vertices at $(2, 0)$, $(-2, 0)$, forming a vertical elongated oval centered at the origin $(0,0)$.
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graph each equation. 9) \\(\\frac{x^2}{4} + \\frac{y^2}{9} = 1\\)
The graph is an ellipse with vertices at $(0, 3)$, $(0, -3)$ and co-vertices at $(2, 0)$, $(-2, 0)$, forming a vertical elongated oval centered at the origin.
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graph each equation. 9) \\(\\frac{x^2}{4} + \\frac{y^2}{9} = 1\\)
The graph is an ellipse centered at the origin $(0,0)$ with vertices at $(0, 3)$, $(0, -3)$ and co-vertices at $(2, 0)$, $(-2, 0)$, forming a vertical elongated oval shape passing…
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graph each equation. 9) \\(\\frac{x^2}{4} + \\frac{y^2}{9} = 1\\)
The graph is an ellipse centered at the origin $(0,0)$ with vertices at $(0, 3)$, $(0, -3)$ and co-vertices at $(2, 0)$, $(-2, 0)$, drawn as a smooth curve connecting these points.
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go for each pair of similar polygons, give three ratios that would be e…
20. $\boldsymbol{\frac{3}{1.5}}$, $\boldsymbol{\frac{5}{3}}$, $\boldsymbol{\frac{c}{a}}$ (or simplified: $\boldsymbol{2}$, $\boldsymbol{\frac{5}{3}}$, $\boldsymbol{\frac{c}{a}}$) …
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19. determine whether or not the pairs of triangles are similar and exp…
a. The triangles are similar. Two pairs of corresponding angles are congruent, satisfying the AA similarity criterion. b. The triangles are not similar. The ratios of correspondin…
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find the volume of this square based pyramid. v = ? cm³
\( 4 \)
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18. one definition of similar triangles is based on transformations. ho…
1. **AA (Angle-Angle) Similarity**: If two angles of one triangle are congruent to two angles of another triangle, the triangles are similar. 2. **SAS (Side-Angle-Side) Similarity…
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given the circle below with chords \\(\\overline{qr}\\) and \\(\\overli…
4.7
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given the circle below with chords \\( \\overline{qr} \\) and \\( \\ove…
4.7
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circle s, m∠utv = 51°. solve for x if muv = (5x + 23)°. if necessary, r…
$x=15.8$
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in circle q, m∠orp = 52°. solve for x if mop = (4x + 39)°. if necessary…
16.3
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in circle v, mtw = 118°. solve for x if m∠utw = (3x + 22)°. if necessar…
$x = 17.3$
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in circle v, muw = 118°. solve for x if m∠utw = (3x + 22)°. if necessar…
$x = 14.7$
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question in circle j, mih = 142°. solve for x if m∠igh = (10x + 36)°. i…
$3.5$
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in circle p, mqo = 131°. solve for x if m∠qpo = (6x + 26)°. if necessar…
$x = 17.5$
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in circle n, m∠onp = 48°. solve for x if mop = (4x - 48)°. if necessary…
$x=36.0$
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given the circle below with chords \\(\\overline{tu}\\) and \\(\\overli…
16.6