Question

what happens the second time dr. hewitt lifts the bowling ball near his teeth and gives it a push? view available hint(s) the ball leaves dr. hewitt and returns to him, going past the point where it was released. the ball returns to dr. hewitt, stopping almost exactly at the point where it was released. the ball leaves dr. hewitt and returns to him, stopping short of the point where it was released. submit part d why does the bowling ball behave as it does when dr. hewitt lifts it and gives it a push? view available hint(s) the extra energy from the push is converted into kinetic energy, which is then converted into more potential energy at the end of the motion than the ball had when it was released. the ball’s initial energy is lost. the ball gains potential energy after it is released. submit

Explanation:

First Question (What happens...):

When a push is given to the bowling ball, it gains extra kinetic energy. This kinetic energy converts to potential energy at the peak. Since there's extra energy from the push, the ball will go past the release point when returning. The second option assumes no extra energy (just release), and the third says it stops short (which would be if energy was lost, but a push adds energy). So the first option is correct.

When pushed, the ball gets extra energy (work done by the push becomes kinetic energy). This kinetic energy is converted to potential energy. So at the end of motion, the potential energy is more than when it was just released (no push), meaning it goes further. The second option is wrong (energy isn't lost; a push adds energy). The third is wrong (potential energy comes from height, and after release, it converts between kinetic and potential, not gaining new potential energy after release without external work, but the push provides external work before release). So the first option explains it.

Answer:

The ball leaves Dr. Hewitt and returns to him, going past the point where it was released.

Part D (Why does the...):