QUESTION IMAGE
Question
solve for x: 2|11x + 1| + 1 = 4
a) ( x = \frac{1}{22}, x = -\frac{5}{22} )
b) ( x = \frac{1}{22} )
c) ( x = -\frac{5}{22} )
d) ( x = \frac{1}{11}, x = -\frac{5}{22} )
e) ( x = \frac{1}{11} )
f) none of the above.
Step1: Isolate the absolute value
Subtract 1 from both sides of the equation \(2|11x + 1|+1 = 4\) to get \(2|11x + 1|=4 - 1\).
Simplify the right side: \(2|11x + 1| = 3\).
Then divide both sides by 2: \(|11x + 1|=\frac{3}{2}\).
Step2: Solve the absolute value equation
The absolute value equation \(|11x + 1|=\frac{3}{2}\) gives two cases:
Case 1: \(11x+1=\frac{3}{2}\)
Subtract 1 from both sides: \(11x=\frac{3}{2}-1\).
Simplify the right side: \(11x=\frac{3 - 2}{2}=\frac{1}{2}\).
Divide both sides by 11: \(x=\frac{1}{2\times11}=\frac{1}{22}\).
Case 2: \(11x + 1=-\frac{3}{2}\)
Subtract 1 from both sides: \(11x=-\frac{3}{2}-1\).
Simplify the right side: \(11x=-\frac{3 + 2}{2}=-\frac{5}{2}\).
Divide both sides by 11: \(x=-\frac{5}{2\times11}=-\frac{5}{22}\).
So the solutions are \(x = \frac{1}{22}\) and \(x=-\frac{5}{22}\), which matches option d (since option d is \(x=\frac{1}{11}\) (wait, no, let's re - check the options. Wait the user's option d: "x = 1/11: x = -5/22" (maybe a typo, but from our solution, the solutions are \(x=\frac{1}{22}\) and \(x = -\frac{5}{22}\)? Wait no, wait in step 2 case 1:
Wait \(11x+1=\frac{3}{2}\)
\(11x=\frac{3}{2}-1=\frac{3 - 2}{2}=\frac{1}{2}\)
\(x=\frac{1}{2\times11}=\frac{1}{22}\)
Case 2: \(11x + 1=-\frac{3}{2}\)
\(11x=-\frac{3}{2}-1=-\frac{3 + 2}{2}=-\frac{5}{2}\)
\(x=-\frac{5}{2\times11}=-\frac{5}{22}\)
Looking at the options:
Option d: "x = 1/11: x = -5/22" (maybe a typo, perhaps it's \(x=\frac{1}{22}\) and \(x = -\frac{5}{22}\), but among the given options, option d has \(x = -\frac{5}{22}\) and a wrong first solution? Wait no, maybe I made a mistake in the original equation. Wait the original equation: "Solve for x: 2|11x + 1|+1 = 4"
Wait let's re - do the first step:
\(2|11x + 1|+1 = 4\)
Subtract 1: \(2|11x + 1|=3\)
Divide by 2: \(|11x + 1|=\frac{3}{2}\)
Then \(11x+1=\frac{3}{2}\) or \(11x + 1=-\frac{3}{2}\)
First equation: \(11x=\frac{3}{2}-1=\frac{1}{2}\), \(x=\frac{1}{22}\)
Second equation: \(11x=-\frac{3}{2}-1=-\frac{5}{2}\), \(x = -\frac{5}{22}\)
Now looking at the options:
a) \(x=\frac{1}{22},x = -\frac{5}{22}\) – wait no, option a is "x = 1/22, x = -5/22"? Wait the user's option a: "x = 1/22, x = -5/22"? Wait the user's image:
a) \(x=\frac{1}{22},x = -\frac{5}{22}\)
b) \(x=\frac{1}{22}\)
c) \(x=-\frac{5}{22}\)
d) \(x=\frac{1}{11}:x = -\frac{5}{22}\)
e) \(x=\frac{1}{11}\)
f) None of the above.
Wait maybe the original problem's option a is correct? Wait no, in the user's image, option a: "x = 1/22, x = -5/22" (the user wrote "x = 1/22, x = -5/22" for option a? Wait the user's text:
"a) x = 1/22, x = -5/22"
"b) x = 1/22"
"c) x = -5/22"
"d) x = 1/11: x = -5/22"
"e) x = 1/11"
"f) None of the above"
Ah, I see, so option a is \(x=\frac{1}{22}\) and \(x = -\frac{5}{22}\), which are the two solutions we found. But in the image, the selected option is b, but that's incorrect. Wait maybe I misread the equation. Wait the original equation: "2|11x + 1|+1 = 4"? Or is it "2|11x + 1|+11 = 4"? No, the user wrote "2|11x + 1|+1 = 4".
Wait let's recalculate:
\(2|11x + 1|+1 = 4\)
\(2|11x + 1|=3\)
\(|11x + 1|=\frac{3}{2}\)
\(11x+1=\frac{3}{2}\) or \(11x + 1=-\frac{3}{2}\)
First solution:
\(11x=\frac{3}{2}-1=\frac{1}{2}\)
\(x=\frac{1}{22}\)
Second solution:
\(11x=-\frac{3}{2}-1=-\frac{5}{2}\)
\(x = -\frac{5}{22}\)
So the correct solutions are \(x=\frac{1}{22}\) and \(x = -\frac{5}{22}\), which is option a. But in the image, option b is selected, which is wrong.
Wait maybe the original equation is \(2|11x + 1|+11 = 4\)? Let's check:
\(2|11x + 1|+11 = 4\…
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A. \(x=\frac{1}{22},x = -\frac{5}{22}\)