Question

rectangular prisms
complete the missing sections within each prism, to calculate the volume of prism 1, multiply length x width x height. for prism 2, use the known values of the mass and density to calculate (round all answers to the nearest tenth).
prism 1
mass 25 g
volume 2.1 cm³
density 11.9 g/cm³
length (2.7 cm)
prism 2
mass 12 g
volume
density 9.2 g/cm³
prism 3
mass 136.5 g
volume 15.7 cm³
density 8.7 g/cm³
directions
step 1: calculate the density of the six liquids. do not round the final answer.
liquid color mass volume density
liquid a blue 50 g 50 ml 1 g/ml
liquid b orange 63.5 g 50 ml 1.27 g/ml
liquid c green 59.5 g 50 ml 1.19 g/ml
liquid d red 82.5 g 50 ml 1.65 g/ml
liquid e pink 40 g 50 ml 0.8 g/ml
liquid f purple 48 g 50 ml 0.96 g/ml
step 2: use the data from the table to label and color the layers in the density column jar. layer c has been labeled for you. hint: less dense objects float on top of more dense objects.

Explanation:

Step1: Recall density formula

The formula for density is $
ho=\frac{m}{V}$, where $
ho$ is density, $m$ is mass and $V$ is volume.

Step2: Calculate density for Liquid A

Given $m = 50\ g$ and $V=50\ mL$, then $
ho_A=\frac{50\ g}{50\ mL}=1\ g/mL$.

Step3: Calculate density for Liquid B

Given $m = 63.5\ g$ and $V = 50\ mL$, then $
ho_B=\frac{63.5\ g}{50\ mL}=1.27\ g/mL$.

Step4: Calculate density for Liquid C

Given $m = 59.5\ g$ and $V = 50\ mL$, then $
ho_C=\frac{59.5\ g}{50\ mL}=1.19\ g/mL$.

Step5: Calculate density for Liquid D

Given $m = 82.5\ g$ and $V = 50\ mL$, then $
ho_D=\frac{82.5\ g}{50\ mL}=1.65\ g/mL$.

Step6: Calculate density for Liquid E

Given $m = 40\ g$ and $V = 50\ mL$, then $
ho_E=\frac{40\ g}{50\ mL}=0.8\ g/mL$.

Step7: Calculate density for Liquid F

Given $m = 48\ g$ and $V = 50\ mL$, then $
ho_F=\frac{48\ g}{50\ mL}=0.96\ g/mL$.

For the rectangular - prisms:

Prism 1

Density $
ho_1=\frac{m_1}{V_1}$, given $m_1 = 25\ g$ and $V_1=2.1\ cm^3$, so $
ho_1=\frac{25\ g}{2.1\ cm^3}\approx11.9\ g/cm^3$.

Prism 2

Given $
ho_2 = 9.2\ g/cm^3$ and $m_2 = 12\ g$, using $
ho=\frac{m}{V}$, we can find $V_2=\frac{m_2}{
ho_2}=\frac{12\ g}{9.2\ g/cm^3}\approx1.3\ cm^3$.

Prism 3

Given $m_3 = 136.5\ g$, $V_3 = 15.7\ cm^3$, then $
ho_3=\frac{m_3}{V_3}=\frac{136.5\ g}{15.7\ cm^3}\approx8.7\ g/cm^3$.

To label the density - column jar:
The liquids should be layered from bottom to top in order of decreasing density. The order of density from highest to lowest is: $D(1.65\ g/mL)>B(1.27\ g/mL)>C(1.19\ g/mL)>A(1\ g/mL)>F(0.96\ g/mL)>E(0.8\ g/mL)$.

Answer:

Liquid A density: $1\ g/mL$
Liquid B density: $1.27\ g/mL$
Liquid C density: $1.19\ g/mL$
Liquid D density: $1.65\ g/mL$
Liquid E density: $0.8\ g/mL$
Liquid F density: $0.96\ g/mL$
Prism 1 density: $11.9\ g/cm^3$
Prism 2 volume: $1.3\ cm^3$
Prism 3 density: $8.7\ g/cm^3$
Density - column jar layering (from bottom - to - top): Liquid D, Liquid B, Liquid C, Liquid A, Liquid F, Liquid E.