Question

7 - m2 - tc - lesson 13

1. -3(4)
2. -2(6)
3. 2(-6)
4. 6(-2)
5. refer to the expression 0 - 3 - 3 to complete parts (a)-(c).

a. write the expression as a repeated addition expression.
b. write the expression as a multiplication expression.
c. evaluate the expression.

Explanation:

Step1: Solve -3(4)

Multiply -3 and 4. $-3\times4=-12$

Step2: Solve -2(6)

Multiply -2 and 6. $-2\times6 = -12$

Step3: Solve 2(-6)

Multiply 2 and -6. $2\times(-6)=-12$

Step4: Solve 6(-2)

Multiply 6 and -2. $6\times(-2)=-12$

Step5: Solve part (a) of question 10

Rewrite subtraction as addition of the opposite. $0 - 3-3=0+(- 3)+(-3)$

Step6: Solve part (b) of question 10

Since we have two - 3's being added to 0, we can write it as a multiplication. $0+(-3)+(-3)=0 + 2\times(-3)$

Step7: Solve part (c) of question 10

First, $0-3=-3$, then $-3 - 3=-6$

Answer:

1. -12
2. -12
3. -12
4. -12

10.
a. $0+(-3)+(-3)$
b. $0 + 2\times(-3)$
c. -6