Question

enter the coordinates of the image after △jkl is reflected across the x-axis.
table with columns jkl and jkl, rows: j(-2,4) with ?, k(-2,2) with ?, l(-4,2) with ?. a graph of △jkl on a coordinate plane (x-axis, y-axis) showing points j, k, l and the reflected triangle below the x-axis.

Explanation:

Step1: Recall reflection over x - axis rule

The rule for reflecting a point \((x,y)\) across the \(x\) - axis is \((x,y)\to(x, - y)\).

Step2: Find \(J'\)

For point \(J(-2,4)\), applying the reflection rule: \(x=-2\), \(y = 4\), so \(J'=(-2,-4)\).

Step3: Find \(K'\)

For point \(K(-2,2)\), applying the reflection rule: \(x=-2\), \(y = 2\), so \(K'=(-2,-2)\).

Step4: Find \(L'\)

For point \(L(-4,2)\), applying the reflection rule: \(x=-4\), \(y = 2\), so \(L'=(-4,-2)\).

Answer:

\(J'(-2,-4)\), \(K'(-2,-2)\), \(L'(-4,-2)\)