Question

1. an elevator in an office - building completed the following trips: 1st floor to 6th floor, 6th floor to 3rd floor, 3rd floor to 11th floor. the distance between each floor is 3 meters. what is the total distance traveled and the displacement of the elevator? d = 51 m and δd = 33 m, d = 30 m and δd = 48 m, d = 48 m and δd = 30 m, d = 33 m and δd = 51 m, clear all

Explanation:

Step1: Calculate distance of 1st - 6th floor

Number of floors = 6 - 1=5. Distance = 5×3 = 15 m.

Step2: Calculate distance of 6th - 3rd floor

Number of floors = 6 - 3 = 3. Distance = 3×3=9 m.

Step3: Calculate distance of 3rd - 11th floor

Number of floors = 11 - 3 = 8. Distance = 8×3 = 24 m.

Step4: Calculate total distance

Total distance \(d=15 + 9+24=48\) m.

Step5: Calculate displacement

Initial floor is 1st, final floor is 11th. Number of floors = 11 - 1 = 10. Displacement \(\Delta d=10\times3 = 30\) m.

Answer:

d = 48 m and \(\Delta d=30\) m