Question

click the arrows to choose an answer from each menu. the volume of ice in shape 1 is choose... cubic centimeters. the volume of ice in shape 2 is choose... cubic centimeters. shape 1 contains choose... ice as shape 2. alicia choose... correct.

Explanation:

Step1: Calculate volume of Shape 1 (pyramid with rectangular base)

The formula for the volume of a pyramid is $V = \frac{1}{3}Bh$, where $B$ is the area of the base and $h$ is the height. For Shape 1, the base is a rectangle with length $4$ cm and width $3$ cm, so $B = 4\times3 = 12$ $cm^2$. The height $h$ is $5$ cm. Then $V_1=\frac{1}{3}\times12\times5$.
$\frac{1}{3}\times12\times5 = 4\times5 = 20$ $cm^3$.

Step2: Calculate volume of Shape 2 (pyramid with triangular base)

For Shape 2, the base is a triangle with base $4$ cm and height $3$ cm, so $B=\frac{1}{2}\times4\times3 = 6$ $cm^2$. The height $h$ is $5$ cm. Then $V_2=\frac{1}{3}\times6\times5$.
$\frac{1}{3}\times6\times5 = 2\times5 = 10$ $cm^3$.

Step3: Compare volumes of Shape 1 and Shape 2

Since $20>10$, Shape 1 contains twice as much ice as Shape 2.

Answer:

The volume of ice in shape 1 is $20$ cubic centimeters.
The volume of ice in shape 2 is $10$ cubic centimeters.
Shape 1 contains twice as much ice as shape 2. (Assuming Alicia's statement is about this comparison, so she is correct if her statement matches this.)