Question

the electric field between two parallel plates is 10.0 v/m. if the plates are 5.0 mm apart and hold a charge of 12 μc, what is the capacitance of the plates? o none of the choices are correct. o 0.24 μf o 600 μf o 240 μf o 60 μf

Explanation:

Step1: Calculate the potential difference

We know that $E=\frac{V}{d}$, where $E = 10.0\ V/m$ is the electric - field strength and $d=5.0\ mm = 5\times10^{- 3}\ m$ is the distance between the plates. So, $V = E\times d$.
$V=10.0\ V/m\times5\times10^{-3}\ m = 0.05\ V$

Step2: Calculate the capacitance

The formula for capacitance is $C=\frac{Q}{V}$, where $Q = 12\ \mu C=12\times10^{-6}\ C$ and $V = 0.05\ V$.
$C=\frac{12\times10^{-6}\ C}{0.05\ V}=240\times10^{-6}\ F = 240\ \mu F$

Answer:

O $240\ \mu F$