Question

use a scale to solve problems.
(image shows a rectangle with ( l = 4 ) in, ( w = 2 ) in, and scale ( 1 ) in : ( 3 ) ft)

Explanation:

Assuming the problem is to find the actual length and width (or maybe area, perimeter) using the scale. Let's assume we need to find the actual length and width first.

Step1: Find actual length

The scale is 1 in : 3 ft, and the drawing length \( l = 4 \) in. So actual length \( L = 4 \times 3 \) ft.
\( L = 12 \) ft

Step2: Find actual width

The drawing width \( w = 2 \) in. So actual width \( W = 2 \times 3 \) ft.
\( W = 6 \) ft
(If we need area, then Step3: Calculate area \( A = L \times W = 12 \times 6 = 72 \) sq ft)

Answer:

If for length: 12 ft, width: 6 ft; if for area: 72 square feet (depending on the actual problem, but since the problem says "use a scale to solve problems" and gives length, width, scale, likely finding actual dimensions or area. Assuming area, the answer is 72 square feet. If dimensions, length 12 ft, width 6 ft.)