Question

for use with pages 48–56
find the perimeter and area of the figure.
1.
14 ft
9 ft
2.
13 in.
12 in.
5 in.
3.
9.5 m

Explanation:

Problem 1 (Rectangle: 14 ft by 9 ft)

Step1: Perimeter of Rectangle

The formula for the perimeter of a rectangle is \( P = 2\times (length + width) \). Here, length \( l = 14 \) ft and width \( w = 9 \) ft.
\( P = 2\times(14 + 9) = 2\times23 = 46 \) ft.

Step2: Area of Rectangle

The formula for the area of a rectangle is \( A = length\times width \).
\( A = 14\times9 = 126 \) square feet.

Step1: Perimeter of Triangle

Perimeter is the sum of all sides. So, \( P = 12 + 5 + 13 = 30 \) in.

Step2: Area of Right Triangle

The formula for the area of a right triangle is \( A=\frac{1}{2}\times base\times height \). Here, base \( b = 12 \) in and height \( h = 5 \) in.
\( A=\frac{1}{2}\times12\times5 = 6\times5 = 30 \) square inches.

Step1: Perimeter of Square

The formula for the perimeter of a square is \( P = 4\times side \). Here, side \( s = 9.5 \) m.
\( P = 4\times9.5 = 38 \) m.

Step2: Area of Square

The formula for the area of a square is \( A = side\times side \) (or \( A = s^{2} \)).
\( A = 9.5\times9.5 = 90.25 \) square meters.

Answer:

Perimeter: \( 46 \) ft, Area: \( 126 \) square feet

Problem 2 (Right Triangle: legs 12 in, 5 in; hypotenuse 13 in)