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4 reflect across y-axis. h( , ) → h( , ) i( , ) → i( , ) j( , ) → j( , …

Question

4 reflect across y-axis.
h( , ) → h( , )
i( , ) → i( , )
j( , ) → j( , )
k( , ) → k( , )

Explanation:

Step1: Find coordinates of H, I, J, K

From the graph, H is at (1, -2), I at (3, -2), J at (5, -6), K at (3, -6).

Step2: Apply reflection over y - axis rule

The rule for reflecting a point \((x,y)\) over the \(y\) - axis is \((x,y)\to(-x,y)\).

  • For \(H(1, - 2)\):

Using the rule, \(x = 1\), so \(-x=-1\), \(y=-2\). So \(H'\) is \((-1,-2)\).

  • For \(I(3, - 2)\):

Using the rule, \(x = 3\), so \(-x = - 3\), \(y=-2\). So \(I'\) is \((-3,-2)\).

  • For \(J(5, - 6)\):

Using the rule, \(x = 5\), so \(-x=-5\), \(y = - 6\). So \(J'\) is \((-5,-6)\).

  • For \(K(3, - 6)\):

Using the rule, \(x = 3\), so \(-x=-3\), \(y=-6\). So \(K'\) is \((-3,-6)\).

Answer:

\(H(1, - 2)\to H'(-1, - 2)\)
\(I(3, - 2)\to I'(-3, - 2)\)
\(J(5, - 6)\to J'(-5, - 6)\)
\(K(3, - 6)\to K'(-3, - 6)\)