Question

please remember to submit your workbook. relationship of variables: when mass is constant listen observe the table. how many times greater must the acceleration of object b be than the acceleration of object a to make the table true? enter your answer as a whole number, like this: 4 mass acceleration force object a 20 kg 9 m/s² 180 n object b 40 kg 1800 n

Explanation:

Step1: Use Newton's second - law formula

According to Newton's second - law $F = ma$, where $F$ is force, $m$ is mass, and $a$ is acceleration. For Object $B$, we can find its acceleration $a_B$. Rearranging the formula gives $a=\frac{F}{m}$.

Step2: Calculate the acceleration of Object $B$

Given $m_B = 40$ kg and $F_B=1800$ N, then $a_B=\frac{F_B}{m_B}=\frac{1800}{40}=45$ m/s².

Step3: Calculate the ratio of accelerations

The acceleration of Object $A$ is $a_A = 9$ m/s². The ratio $\frac{a_B}{a_A}=\frac{45}{9}=5$.

Answer:

5