Question

newtons third law quick check a force of 30 n to the right is applied to an object. an opposite force of 20 n to the left is applied to the same object. what is the net force applied to the object? (1 point) 10 n to the right 50 n to the right 50 n to the left 10 n to the left

Explanation:

Step1: Define positive direction

Let right be positive, so force to the right is \( +30\,\text{N} \), force to the left is \( -20\,\text{N} \).

Step2: Calculate net force

Net force \( F_{\text{net}} = F_1 + F_2 = 30\,\text{N}+(- 20\,\text{N}) = 10\,\text{N} \). Positive sign means direction is right.

Answer:

10 N to the right