Question

$6\frac{2}{3}div - 1\frac{7}{9}$

Explanation:

Step1: Convert mixed - numbers to improper fractions

$6\frac{2}{3}=\frac{6\times3 + 2}{3}=\frac{20}{3}$ and $-1\frac{7}{9}=-\frac{1\times9+7}{9}=-\frac{16}{9}$

Step2: Rewrite the division as multiplication

Dividing by a fraction is the same as multiplying by its reciprocal. So $\frac{20}{3}\div(-\frac{16}{9})=\frac{20}{3}\times(-\frac{9}{16})$

Step3: Multiply the numerators and denominators

$\frac{20\times(- 9)}{3\times16}=\frac{-180}{48}$

Step4: Simplify the fraction

$\frac{-180\div12}{48\div12}=-\frac{15}{4}=-3\frac{3}{4}$

Answer:

$-3\frac{3}{4}$