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independent practice henry is playing memory with different math cards.…

Question

independent practice
henry is playing memory with different math cards. solve for x on each card and record the matching sets below.
a $7x - 28 = 14$
b $9x - 9 = 18$
c $\frac{x}{7}+ 5 = 8$
d $37 = 32 + \frac{x}{10}$
e $\frac{x}{4}+ 9 = 11$
f $4x - 16 = 32$
g $5x + 27 = 32$
h $2x - 8.7 = 21.3$
i $48 = 3x - 15$
j $0.5x + 15 = 18$
k $8 + \frac{x}{3}= 13$
l $8x - 2.5 = 5.5$
m $\frac{x}{5}+ 7 = 17$
n $84 = 24 + 5x$
o $14 = 3x - 10$
p $5x - 7.4 = 7.6$
then there are boxes for each letter (a - p) to record the value of x with x = in each box.

Explanation:

Response
Card A: \( 7x - 28 = 14 \)

Step 1: Add 28 to both sides

\( 7x - 28 + 28 = 14 + 28 \)
\( 7x = 42 \)

Step 2: Divide both sides by 7

\( \frac{7x}{7} = \frac{42}{7} \)
\( x = 6 \)

Step 1: Add 9 to both sides

\( 9x - 9 + 9 = 18 + 9 \)
\( 9x = 27 \)

Step 2: Divide both sides by 9

\( \frac{9x}{9} = \frac{27}{9} \)
\( x = 3 \)

Step 1: Subtract 5 from both sides

\( \frac{x}{7} + 5 - 5 = 8 - 5 \)
\( \frac{x}{7} = 3 \)

Step 2: Multiply both sides by 7

\( x = 3 \times 7 \)
\( x = 21 \)

Answer:

\( x = 6 \)

Card B: \( 9x - 9 = 18 \)