Question

identify a pair of segments that are marked perpendicular to each other on the diagram below. (diagram is not to scale.) answer attempt 1 out of 2 is perpendicular to

Explanation:

Step1: Recall Perpendicular Definition

Perpendicular segments form a right angle (90°). Look for right - angle marks or segments forming 90° in the diagram.

Step2: Analyze the Diagram

In the diagram, segment \( TS \) and segment \( PS \) (or \( RS \), \( QS \)): The right - angle mark at \( S \) shows that \( TS \perp PS \) (or \( TS \perp RS \), \( TS \perp QS \), also \( XQ \perp PS \), \( YR \perp PS \), \( VW \perp PS \) etc. Another pair: \( XQ \) and \( WX \)? No, the right - angle at \( X \) (the arc marks) and at \( T \) (arc marks) and the right - angle at \( S \). Let's take \( TS \) and \( PS \): The right - angle symbol at \( S \) between \( TS \) and \( PS \) (or \( RS \), \( QS \)) indicates perpendicularity. Also, \( XQ \) and \( PQ \) (since \( XQ \) is vertical and \( PQ \) is horizontal, with the right - angle at \( Q \) implied by the diagram structure). But a clear pair is \( TS \) and \( PS \) (or \( TS \) and \( RS \), \( TS \) and \( QS \), \( XQ \) and \( PQ \), \( XQ \) and \( QR \), \( YR \) and \( QR \), \( YR \) and \( RS \), \( VW \) and \( PQ \), \( VW \) and \( QR \), \( VW \) and \( RS \)). Let's pick \( TS \) and \( PS \) (or \( SU \) and \( TS \)? No, \( SU \) and \( TS \): Wait, \( SU \) is vertical, \( TS \) is horizontal? Wait, the diagram has \( S \) with a right - angle, so \( TS \perp PS \) (since \( PS \) is horizontal and \( TS \) is vertical at \( S \)). Also, \( XQ \) is vertical, \( WX \) is horizontal? Wait, the arc marks at \( X \) and \( T \) indicate right angles between the horizontal (like \( WX \), \( XY \), \( YT \)) and vertical ( \( XQ \), \( YR \), \( TS \)) segments. So a pair like \( XQ \) and \( WX \) (or \( XQ \) and \( X Y \)? No, \( WX \) and \( XQ \): the arc at \( X \) shows a right angle between \( WX \) (horizontal) and \( XQ \) (vertical). Similarly, \( YR \) and \( YT \) (arc at \( T \) shows right angle between \( YT \) (horizontal) and \( YR \) (vertical)), and \( TS \) and \( SU \) (wait, \( SU \) is vertical, \( TS \) is horizontal, and the right - angle at \( S \) between \( TS \) and \( SU \)? Wait, \( S \) has a right - angle, so \( TS \perp SU \)? No, \( SU \) is from \( S \) to \( U \), and \( TS \) is from \( T \) to \( S \). Wait, the horizontal line is \( PQRS \), and vertical lines are \( VW \), \( XQ \), \( YR \), \( SU \). The horizontal segments are \( WV \), \( WX \), \( XY \), \( YT \), \( TU \), and vertical segments are \( VP \), \( WQ \), \( XR \), \( YS \)? No, let's re - look. The diagram: \( P \), \( Q \), \( R \), \( S \) are on a horizontal line. \( V \) is above \( P \), \( W \) above \( Q \), \( X \) above \( Q \)? Wait, no, \( W \) is on \( VP \), \( X \) is on \( WX \) (horizontal) and \( XQ \) (vertical). The arc marks at \( X \) and \( T \) are right angles, meaning that the horizontal segment (like \( WX \) or \( YT \)) and vertical segment (like \( XQ \) or \( YR \)) are perpendicular. Also, at \( S \), the right - angle mark means \( TS \perp PS \) (or \( TS \perp RS \), \( TS \perp QS \)). So a valid pair is \( TS \) and \( PS \) (or \( XQ \) and \( PQ \), \( YR \) and \( QR \), \( VW \) and \( PQ \), etc.). Let's take \( TS \) and \( PS \): the right - angle at \( S \) shows they are perpendicular.

Answer:

\( TS \) is perpendicular to \( PS \) (or other valid pairs like \( XQ \) and \( PQ \), \( YR \) and \( QR \), \( VW \) and \( PQ \), \( XQ \) and \( WX \), \( YR \) and \( YT \), \( TS \) and \( SU \) etc. One of the correct pairs is \( TS \) and \( PS \))