Question

an ideal gas exerts a pressure of 3 atm in a 3 l container. the container is at a temperature of 298 °c. what will be the final pressure if the temperature stays the same and the volume of the container changes to 2 l?
0.54 atm
4.5 atm
2 atm
2.25 atm

Explanation:

Step1: Identify the relevant gas - law

Since the temperature is constant, we use Boyle's Law, which is $P_1V_1 = P_2V_2$.

Step2: Assign values to variables

$P_1 = 3$ atm, $V_1 = 3$ L, and $V_2 = 2$ L. We need to find $P_2$.

Step3: Rearrange the formula to solve for $P_2$

From $P_1V_1 = P_2V_2$, we can get $P_2=\frac{P_1V_1}{V_2}$.

Step4: Substitute the values

$P_2=\frac{3\ atm\times3\ L}{2\ L}=\frac{9}{2}= 4.5$ atm.

Answer:

4.5 atm