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complete the scrambled multiplication table.

Question

complete the scrambled multiplication table.

Explanation:

Response

To solve the scrambled multiplication table, we use the basic multiplication rule \( a\times b = c \), where \( a \) is the row number, \( b \) is the column number, and \( c \) is the product. We'll fill in the missing values row by row or column by column, using known products to find unknown factors.

Step 1: Identify Row and Column Headers

First, we determine the row and column headers (the first column and first row, excluding the "×" cell) by finding the factors of the known products. For example:

  • In the row with "4" (first column), the product with column "5" is \( 4\times5 = 20 \) (matches), with column "6" is \( 4\times6 = 24 \) (matches), and with column "3" is \( 4\times3 = 12 \) (matches). So row "4" is correct.
  • In the column with "5" (first row), the product with row "5" (let's check the row with product "25" in column "5": \( 5\times5 = 25 \)), so row "5" (first column) has "5".
  • In the column with "2" (first row), the product with row "8" is \( 8\times2 = 16 \) (matches), with row "5" is \( 5\times2 = 10 \) (matches), so column "2" is correct.
Step 2: Fill in Missing Column Headers (First Row)

The first row (column headers) has missing values. Let's find them using row products:

  • For the cell in row "4", column (unknown): \( 4\times x = 36 \) ⇒ \( x = \frac{36}{4} = 9 \). So column "9" (first row) is 9.
  • For the cell in row "1", column (unknown) with product "8": \( 1\times x = 8 \) ⇒ \( x = 8 \). So column "8" (first row) is 8.
  • For the cell in row "1", column (unknown) with product "7": \( 1\times x = 7 \) ⇒ \( x = 7 \). So column "7" (first row) is 7.
  • For the cell in row "1", column (unknown) with product "1": \( 1\times x = 1 \) ⇒ \( x = 1 \). So column "1" (first row) is 1.
  • For the cell in row "9", column (unknown) with product "3": \( 9\times x = 3 \) ⇒ \( x = \frac{3}{9} = \frac{1}{3} \)? No, wait—row "9" (first column) is actually "3"? Wait, no, row "9" (first column) has product "15" with column "5": \( 3\times5 = 15 \), so row "9" (first column) is "3" (since \( 3\times5 = 15 \)). Let's correct: row "3" (first column) has "3", because \( 3\times5 = 15 \), \( 3\times2 = 6 \), \( 3\times1 = 3 \). So row "3" (first column) is 3.
  • For the cell in row "7", column (unknown) with product "63": \( 7\times x = 63 \) ⇒ \( x = 9 \) (already known, column "9").
  • For the cell in row "5", column (unknown) with product "5": \( 5\times x = 5 \) ⇒ \( x = 1 \) (column "1", already known).
  • For the cell in row "6", column (unknown) with product "48": \( 6\times x = 48 \) ⇒ \( x = 8 \) (column "8", already known).
  • For the cell in row "9" (first column "9"), column (unknown) with product "72": \( 9\times x = 72 \) ⇒ \( x = 8 \) (column "8", already known).
  • For the cell in row "2" (first column "2"), column (unknown) with product "10": \( 2\times x = 10 \) ⇒ \( x = 5 \) (column "5", already known), product "8": \( 2\times x = 8 \) ⇒ \( x = 4 \) (column "4", already known), product "14": \( 2\times x = 14 \) ⇒ \( x = 7 \) (column "7", already known), product "6": \( 2\times x = 6 \) ⇒ \( x = 3 \) (column "3", already known), product "2": \( 2\times x = 2 \) ⇒ \( x = 1 \) (column "1", already known), product "12": \( 2\times x = 12 \) ⇒ \( x = 6 \) (column "6", already known). So row "2" (first column) is 2.
Step 3: Fill in Missing Row Headers (First Column)

The first column (row headers) has missing values. Let's confirm:

  • Row with product "25" in column "5": \( 5\times5 = 25 \), so row "5" (first column) is 5.
  • Row with product "30" in column "5": \( 6\times5 = 30 \), so row "6" (first column) is…

Answer:

The completed multiplication table (key cells) is as shown above, with each cell calculated as \( \text{row} \times \text{column} \).