Question

1. christopher ran 16 miles at 50 degrees south of west. how far west did christopher run?

○ −10.3 miles west
○ 12.3 miles west
○ 48.1 miles west
○ 10.3 miles west

Explanation:

Answer:

D. 10.3 miles west

(Note: To find the westward component, we use the cosine of the angle. The distance west is \( 16 \cos(50^\circ) \approx 16 \times 0.6428 \approx 10.3 \) miles. So the correct option is 10.3 miles west.)