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8.) v = ⅓ ah; v = 45, h = 5 (volume of a pyramid)

Question

8.) v = ⅓ ah; v = 45, h = 5 (volume of a pyramid)

Explanation:

Step1: Substitute given values into formula

We know the formula for the volume of a pyramid is \( V=\frac{1}{3}Ah \), and we are given \( V = 45 \) and \( h=5 \). Substitute these values into the formula: \( 45=\frac{1}{3}\times A\times5 \)

Step2: Solve for A

First, simplify the right - hand side of the equation: \( 45=\frac{5}{3}A \)
To isolate \( A \), multiply both sides of the equation by \( \frac{3}{5} \). So \( A = 45\times\frac{3}{5} \)
Calculate \( 45\times\frac{3}{5}=\frac{45\times3}{5}=9\times3 = 27 \)

Answer:

The value of \( A \) is \( 27 \)