Question

13 an airplane accelerates at 12.00 m/s² from rest. if it lifts off from an aircraft carrier after 5.00 s, how far did it go down the runway before lift off? a 720.0 m b 150.0 m c 30.0 m d 600.0 m

Explanation:

Step1: Identify the kinematic - equation

The airplane starts from rest ($v_0 = 0$), and we use the equation $x=v_0t+\frac{1}{2}at^{2}$.

Step2: Substitute the values

Given $v_0 = 0\ m/s$, $a = 12.00\ m/s^{2}$, and $t = 5.00\ s$. Substituting into the equation: $x=(0\times5)+\frac{1}{2}\times12\times(5)^{2}$.

Step3: Calculate the result

First, calculate $(5)^{2}=25$. Then, $\frac{1}{2}\times12\times25 = 6\times25=150\ m$.

Answer:

B. 150.0 m