Question

a 3.0 - kg bowling ball experiences a net force of 8.0 n. what will be its acceleration?
24 m/s²
3.0 m/s²
8.0 m/s²
2.7 m/s²
0.38 m/s²
question 4 10 pts
two forces act on a 8.50 - kg object. one of the forces is 14.0 n. if the object accelerates at 3.50 m/s², what is the greatest possible magnitude of the other force?
10 n
15.8 n
43.8 n
26.3 n
73.5 n

Explanation:

Step1: Recall Newton's second - law formula

$F = ma$, where $F$ is the net force, $m$ is the mass, and $a$ is the acceleration. We can solve for $a$ as $a=\frac{F}{m}$.

Step2: Calculate acceleration for first question

Given $m = 3.0\ kg$ and $F = 8.0\ N$, then $a=\frac{8.0\ N}{3.0\ kg}\approx2.67\ m/s^{2}\approx2.7\ m/s^{2}$.

Step3: For the second question, first find the net force

Using $F = ma$, with $m = 8.50\ kg$ and $a = 3.50\ m/s^{2}$, the net force $F_{net}=ma=8.50\ kg\times3.50\ m/s^{2}=29.75\ N$.

Step4: Determine the other force

Let the two forces be $F_1$ and $F_2$. The net force $F_{net}=F_1 + F_2$ (when the forces are in the same direction for maximum magnitude of the other force). Given $F_1 = 14.0\ N$, then $F_2=F_{net}-F_1$. So $F_2=29.75\ N - 14.0\ N=15.75\ N\approx15.8\ N$.

Answer:

First question: $2.7\ m/s^{2}$ (closest option is $2.7\ m/s^{2}$ which is not exactly listed but closest to the calculated value)
Second question: B. $15.8\ N$