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use the equation to solve for the area of the inner square. start by fi…

Question

use the equation to solve for the area of the inner square. start by finding the area of the outer square. area of outer square - sum of the areas of the 4 triangles = area of inner square

Explanation:

Step1: Determine outer square side length

From the grid, the outer square has a side length of 8 units (counting the grid squares). The area of a square is \( \text{side}^2 \), so the area of the outer square is \( 8 \times 8 = 64 \) square units.

Step2: Analyze the 4 triangles

Each of the 4 triangles is a right triangle with legs of length 4 units (since the outer square side is 8, and the triangles are formed by dividing the sides into two equal parts). The area of one triangle is \( \frac{1}{2} \times \text{base} \times \text{height} = \frac{1}{2} \times 4 \times 4 = 8 \) square units.

Step3: Calculate sum of 4 triangles' areas

There are 4 such triangles, so the total area of the 4 triangles is \( 4 \times 8 = 32 \) square units.

Step4: Find inner square area

Using the given equation: \( \text{Area of outer square} - \text{Sum of areas of 4 triangles} = \text{Area of inner square} \). Substituting the values: \( 64 - 32 = 32 \) square units.

Answer:

The area of the inner square is 32 square units. The area of the outer square is 64 square units, the sum of the areas of the 4 triangles is 32 square units, and the area of the inner square is 32 square units.