Question

1. right angles xpf and bwy are shown. ray ph is inside ∠xpf, such that m∠hpf = 39° and m∠hpf = m∠kwy. what is m∠bwk?

Explanation:

Step1: Identify right angle measure

A right angle is \( 90^\circ \), so \( m\angle BWY = 90^\circ \).

Step2: Find \( m\angle KWY \)

Given \( m\angle HPF = m\angle KWY \) and \( m\angle HPF = 39^\circ \), so \( m\angle KWY = 39^\circ \).

Step3: Calculate \( m\angle BWK \)

Since \( \angle BWY = \angle BWK + \angle KWY \), then \( m\angle BWK = m\angle BWY - m\angle KWY \). Substituting values: \( m\angle BWK = 90^\circ - 39^\circ = 51^\circ \).

Answer:

\( 51^\circ \)