Question

problem 3: a car travels 5 meters in 2 seconds. the car then stays motionless for 2 seconds. it then moves 5 meters in the opposite direction in 4 seconds. last, the car moves forward at 3m/s for 2 seconds. a. what is the velocity of the car for the first 2 seconds? b. what is the velocity of the car from times 4 - 8 seconds? c. how far did the car move from 8 - 10s? position - time graph position (m) 0 1 2 3 4 5 6 7 8 9 10 time (s) 0 1 2 3 4 5 6 7 8 9 10

Explanation:

for a:

Step1: Velocity formula

$v = \frac{\Delta x}{\Delta t}$

Step2: Substitute values

$\Delta x = 5\ \text{m}, \Delta t = 2\ \text{s}$, so $v = \frac{5}{2} = 2.5\ \text{m/s}$

for b:

Step1: Determine time interval

$\Delta t = 8 - 4 = 4\ \text{s}$

Step2: Displacement (opposite direction)

$\Delta x = -5\ \text{m}$

Step3: Calculate velocity

$v = \frac{-5}{4} = -1.25\ \text{m/s}$

for c:

Step1: Time interval

$\Delta t = 10 - 8 = 2\ \text{s}$

Step2: Distance formula

$\text{Distance} = v \times \Delta t$

Step3: Substitute values

$v = 3\ \text{m/s}$, so $\text{Distance} = 3 \times 2 = 6\ \text{m}$

Answer:

a. 2.5 m/s
b. -1.25 m/s
c. 6 m