Question

1. if an object is an irregularly shaped solid and it is dropped into a graduated cylinder and it displaces 25 ml of water and has a mass of 50 grams what is the density of this irregular shaped object?

Explanation:

Step1: Recall density formula

Density ($
ho$) is defined as mass ($m$) divided by volume ($V$), so the formula is $
ho = \frac{m}{V}$.

Step2: Identify mass and volume

The mass of the object $m = 50$ grams. The volume of the object is equal to the volume of water it displaces, so $V = 25$ mL (since 1 mL of water has a volume of 1 $cm^3$, and volume in $cm^3$ is equivalent to volume in mL for water displacement here).

Step3: Calculate density

Substitute the values into the formula: $
ho=\frac{50\ g}{25\ mL}=2\ g/mL$ (or $2\ g/cm^3$ since $1\ mL = 1\ cm^3$).

Answer:

The density of the irregular - shaped object is $2\ g/mL$ (or $2\ g/cm^3$).