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Question
inch-based rule
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copyright goodheart-willcox co., inc.
To solve the problem of reading the inch - based rule, we need to understand the markings on the ruler. The top scale has markings from 1 to 11, and the bottom scale has markings from 12 to 24. Each small division on the ruler represents a fraction of an inch. Let's take the first few problems as examples:
Problem 1
Step 1: Identify the marking
The first marking (top, mark 1) is at the 16th small division from the start (if we consider the left - most as 0). Since there are 16 small divisions in an inch (for the top scale with 16ths), the length is $\frac{1}{16}$ inch? Wait, no, looking at the bottom scale (12 - 24) and top (1 - 11). Wait, actually, the top scale: the first mark (1) is at 1 inch? No, wait the ruler is an inch - based rule. Let's re - examine.
Wait, the top scale: the first mark (1) is at 1 inch? No, the left - most of the top scale is at 1 inch? Wait, the bottom scale: the first mark (12) is at 0 inches? Wait, maybe the top scale is in 16ths of an inch and the bottom scale is in 32nds? Wait, the top scale has marks 1 - 11, with each major mark (1,2,3,...) representing 1 inch, and the small divisions between them are 16ths of an inch. The bottom scale has marks 12 - 24, with small divisions being 32nds of an inch.
Problem 1 (top mark 1)
Step 1: Determine the value
The top mark 1 is at 1 inch? No, wait the left - most of the top scale is at 1 inch? Wait, no, the first mark (top, 1) is at $\frac{1}{16}$ inch? Wait, maybe I got it wrong. Let's start over.
Looking at the ruler:
- For the top scale (1 - 11): Each inch is divided into 16 equal parts. So the value of each small division is $\frac{1}{16}$ inch.
- For the bottom scale (12 - 24): Each inch is divided into 32 equal parts. So the value of each small division is $\frac{1}{32}$ inch.
Problem 1 (top mark 1)
Step 1: Read the top scale
The top mark 1 is at the first small division after 0 (if we consider the left - most as 0). Wait, no, the left - most of the top scale is at 1 inch? No, the label "16" is below the first top mark (1). So 16 small divisions make 1 inch, so each small division is $\frac{1}{16}$ inch. So the first top mark (1) is at $\frac{1}{16}$ inch? Wait, no, the number 16 is below the first top mark (1), so the length from the left - most to mark 1 is $\frac{1}{16}$ inch? No, maybe the top scale is marked in 16ths of an inch, so mark 1 (top) is at $\frac{1}{16}$ inch, mark 2 (top) is at $\frac{2}{16}=\frac{1}{8}$ inch? Wait, no, the second top mark (2) is at $\frac{1}{8}$ inch? Wait, the bottom scale: mark 12 is at 0, mark 13 is at $\frac{1}{32}$ inch? No, this is getting confusing. Let's use the standard inch ruler:
A standard inch ruler has 16ths ($\frac{1}{16}$) and 32nds ($\frac{1}{32}$) of an inch. The top scale here (1 - 11) is probably in 16ths, and the bottom (12 - 24) in 32nds.
Problem 1 (top mark 1)
Step 1: Calculate the length
The top mark 1 is at 16 small divisions? No, the number 16 is below mark 1 (top). So the length is $\frac{1}{16}$ inch? Wait, no, 16 small divisions make 1 inch, so each small division is $\frac{1}{16}$ inch. So mark 1 (top) is at $\frac{1}{16}$ inch.
Problem 2 (top mark 2)
Step 1: Calculate the length
Mark 2 (top) is at 32 small divisions? No, mark 2 (top) is at 2 small divisions of 16ths? Wait, no, the second top mark (2) is at $\frac{2}{16}=\frac{1}{8}$ inch? Wait, the bottom mark 13 is at $\frac{1}{32}$ inch? No, maybe the bottom scale is in 32nds, so mark 12 is 0, mark 13 is $\frac{1}{32}$, mark 14 is $\frac{2}{32}=\frac{1}{16}$, etc.
Let's do problem 1 (top mark…
Step 1: Identify the scale
The top scale is in 16ths of an inch. Mark 1 is at the 1st division of the 16 - division per inch scale.
The length is $\frac{1}{16}$ inch.
Step 1: Identify the scale
The top scale is in 16ths of an inch. Mark 2 is at the 2nd division of the 16 - division per inch scale.
The length is $\frac{2}{16}=\frac{1}{8}$ inch.
Step 1: Identify the scale
The top scale is in 16ths of an inch. Mark 3 is at the 4th division of the 16 - division per inch scale (since it's aligned with the 4th small division).
The length is $\frac{4}{16}=\frac{1}{4}$ inch.
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$\frac{1}{16}$ inch