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find the area of a circle with a circumference of 6.28 units.

Question

find the area of a circle with a circumference of 6.28 units.

Explanation:

Step1: Recall the formula for circumference of a circle

The formula for the circumference \( C \) of a circle is \( C = 2\pi r \), where \( r \) is the radius. We know \( C = 6.28 \) units. Let's solve for \( r \).
\( 6.28 = 2\pi r \)
Assuming \( \pi \approx 3.14 \), we have:
\( 6.28 = 2\times3.14\times r \)
\( 6.28 = 6.28r \)
Dividing both sides by \( 6.28 \):
\( r=\frac{6.28}{6.28}=1 \) unit.

Step2: Recall the formula for area of a circle

The formula for the area \( A \) of a circle is \( A=\pi r^{2} \). Now that we know \( r = 1 \) unit and \( \pi\approx3.14 \), we substitute \( r \) into the formula.
\( A = 3.14\times(1)^{2} \)
\( A = 3.14\times1 \)
\( A = 3.14 \)

Answer:

\( 3.14 \)