Question

equations with parentheses quick check. for which equation is the order of steps to first divide both sides by 6 and then to add 8 to both sides? (1 point) 6(x - 8) = 48; 8(x - 6) = 48; 6(x + 8) = 48; 6x - 8 = 48

Explanation:

Step1: Analyze the first option

For the equation $6(x - 8)=48$, first divide both sides by 6: $\frac{6(x - 8)}{6}=\frac{48}{6}$, which simplifies to $x - 8 = 8$. Then add 8 to both sides: $x-8 + 8=8 + 8$, getting $x = 16$.

Step2: Analyze the second option

For the equation $8(x - 6)=48$, first divide both sides by 8: $\frac{8(x - 6)}{8}=\frac{48}{8}$, giving $x - 6=6$. This does not match the required steps.

Step3: Analyze the third option

For the equation $6(x + 8)=48$, first divide both sides by 6: $\frac{6(x + 8)}{6}=\frac{48}{6}$, resulting in $x + 8 = 8$. Then we should subtract 8, not add 8.

Step4: Analyze the fourth option

For the equation $6x-8 = 48$, we would first add 8 to both sides, not divide by 6 first.

Answer:

$6(x - 8)=48$