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Question
arithmetic sequences practice # 1
- is the sequence arithmetic or not?
{8, 16, 32, 64...}
- find the next 3 terms in the sequence.
{-5, -1, 3, 7, 11...}
- is the sequence finite or infinite?
{14, 9, 4, -1, -6...}
- what is the common difference in this sequence?
{82, 18, -46, -110}
- find the next 5 terms in the sequence.
{16, 25, 34...}
- the first term in a sequence is 15. the common difference is -4. write the first 5 terms of the sequence.
- write an explicit rule for the nth term of the sequence: {3, 16, 29...}. then find a₂₄.
- write an explicit rule for the nth term of the sequence: {94, 67, 40...}. then find a₇₅.
Step1: Recall arithmetic - sequence properties
An arithmetic sequence has a common difference \(d=a_{n + 1}-a_{n}\).
Step2: Solve problem 2
The common difference \(d = 4\) for the sequence \(\{-5,-1,3,7,11,\cdots\}\).
The next 3 terms:
\(a_{6}=11 + 4=15\)
\(a_{7}=15 + 4 = 19\)
\(a_{8}=19+4 = 23\)
Step3: Solve problem 4
For the sequence \(\{82,18,-46,-110,\cdots\}\), \(d=18 - 82=-64\)
Step5: Solve problem 5
The common difference \(d = 9\) for the sequence \(\{16,25,34,\cdots\}\)
The next 5 terms:
\(a_{4}=34 + 9=43\)
\(a_{5}=43 + 9 = 52\)
\(a_{6}=52+9 = 61\)
\(a_{7}=61 + 9=70\)
\(a_{8}=70+9 = 79\)
Step6: Solve problem 6
The first - term \(a_{1}=15\) and \(d=-4\)
The first 5 terms:
\(a_{1}=15\)
\(a_{2}=15-4 = 11\)
\(a_{3}=11-4 = 7\)
\(a_{4}=7-4 = 3\)
\(a_{5}=3-4=-1\)
Step7: Solve problem 8
For the sequence \(\{3,16,29,\cdots\}\), \(a_{1}=3\) and \(d = 13\)
The explicit rule \(a_{n}=a_{1}+(n - 1)d=3+(n - 1)\times13=3+13n-13=13n - 10\)
\(a_{24}=13\times24-10=312 - 10=302\)
Step8: Solve problem 9
For the sequence \(\{94,67,40,\cdots\}\), \(a_{1}=94\) and \(d=-27\)
The explicit rule \(a_{n}=a_{1}+(n - 1)d=94+(n - 1)\times(-27)=94-27n + 27=121-27n\)
\(a_{75}=121-27\times75=121 - 2025=-1904\)
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- \(15,19,23\)
- \(-64\)
- \(43,52,61,70,79\)
- \(15,11,7,3,-1\)
- Explicit rule: \(a_{n}=13n - 10\), \(a_{24}=302\)
- Explicit rule: \(a_{n}=121-27n\), \(a_{75}=-1904\)