QUESTION IMAGE
Question
student handout: unit 3 lesson 2
- complete the following chart.
14
| object | actual measurement | mm | cm | m | km |
|---|---|---|---|---|---|
| length of bulletin board | |||||
| diameter of a dime | |||||
| width of a student’s desk | |||||
| width of the teacher’s desk | |||||
| length of a new pencil | |||||
| length of a small paper clip | |||||
| length of the classroom |
Step1: Recall conversion factors
1 cm = 10 mm, 1 m = 100 cm, 1 km = 1000 m.
Step2: Estimate actual measurements
- Length of bulletin board: Let's assume 150 cm.
- In mm: $150\times10 = 1500$
- In m: $150\div100=1.5$
- In km: $1.5\div1000 = 0.0015$
- Diameter of a dime: Assume 18 mm (or 1.8 cm).
- In cm: 1.8
- In m: $1.8\div100 = 0.018$
- In km: $0.018\div1000=0.000018$
- Width of a student's desk: Assume 60 cm.
- In mm: $60\times10 = 600$
- In m: $60\div100 = 0.6$
- In km: $0.6\div1000=0.0006$
- Width of the teacher's desk: Assume 120 cm.
- In mm: $120\times10 = 1200$
- In m: $120\div100 = 1.2$
- In km: $1.2\div1000 = 0.0012$
- Length of a new pencil: Assume 18 cm.
- In mm: $18\times10 = 180$
- In m: $18\div100 = 0.18$
- In km: $0.18\div1000=0.00018$
- Length of a small paper - clip: Assume 30 mm (or 3 cm).
- In cm: 3
- In m: $3\div100 = 0.03$
- In km: $0.03\div1000=0.00003$
- Length of the classroom: Assume 800 cm (or 8 m).
- In mm: $800\times10 = 8000$
- In m: 8
- In km: $8\div1000 = 0.008$
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| Object | Actual Measurement | mm | cm | m | km |
|---|---|---|---|---|---|
| length of bulletin board | 150 cm | 1500 | 150 | 1.5 | 0.0015 |
| diameter of a dime | 1.8 cm | 18 | 1.8 | 0.018 | 0.000018 |
| width of a student's desk | 60 cm | 600 | 60 | 0.6 | 0.0006 |
| width of the teacher's desk | 120 cm | 1200 | 120 | 1.2 | 0.0012 |
| length of a new pencil | 18 cm | 180 | 18 | 0.18 | 0.00018 |
| length of a small paper clip | 3 cm | 30 | 3 | 0.03 | 0.00003 |
| length of the classroom | 8 m | 8000 | 800 | 8 | 0.008 |