Question

1. $8.32\times10^{-2}\text{ kg}(\frac{;;;;;;;;;;;;}{;;;;;;;;;;;;})=\text{;;;;;;;;;;;; grams}$
2. $55.5\text{ ml}(\frac{;;;;;;;;;;;;}{;;;;;;;;;;;;})=\text{;;;;;;;;;;;; cm}^3$
3. $0.00527\text{ cal}(\frac{;;;;;;;;;;;;}{;;;;;;;;;;;;})=\text{;;;;;;;;;;;; kilocalories}$
4. $9.52\times10^{-4}\text{ m}(\frac{;;;;;;;;;;;;}{;;;;;;;;;;;;})=\text{;;;;;;;;;;;; micrometers}$
5. $41.0\text{ ml}(\frac{;;;;;;;;;;;;}{;;;;;;;;;;;;})=\text{;;;;;;;;;;;; liters}$

Explanation:

Step1: Recall kg - g conversion

We know that 1 kg = 1000 g or $\frac{1000\ g}{1\ kg}$.
$8.32\times10^{-2}\text{ kg}\times\frac{1000\ g}{1\ kg}=8.32\times10^{-2}\times10^{3}\ g = 83.2\ g$

Step2: Recall mL - $cm^{3}$ conversion

1 mL = 1 $cm^{3}$, so the conversion factor is $\frac{1\ cm^{3}}{1\ mL}$.
$55.5\ mL\times\frac{1\ cm^{3}}{1\ mL}=55.5\ cm^{3}$

Step3: Recall cal - kcal conversion

1 kcal = 1000 cal, so the conversion factor is $\frac{1\ kcal}{1000\ cal}$.
$0.00527\ cal\times\frac{1\ kcal}{1000\ cal}=5.27\times 10^{-6}\ kcal$

Step4: Recall m - $\mu$m conversion

1 m = $10^{6}$ $\mu$m, so the conversion factor is $\frac{10^{6}\ \mu m}{1\ m}$.
$9.52\times10^{-4}\ m\times\frac{10^{6}\ \mu m}{1\ m}=952\ \mu m$

Step5: Recall mL - L conversion

1 L = 1000 mL, so the conversion factor is $\frac{1\ L}{1000\ mL}$.
$41.0\ mL\times\frac{1\ L}{1000\ mL}=0.041\ L$

Answer:

1. $83.2$ grams (conversion factor: $\frac{1000\ g}{1\ kg}$)
2. $55.5$ $cm^{3}$ (conversion factor: $\frac{1\ cm^{3}}{1\ mL}$)
3. $5.27\times 10^{-6}$ kilocalories (conversion factor: $\frac{1\ kcal}{1000\ cal}$)
4. $952$ micrometers (conversion factor: $\frac{10^{6}\ \mu m}{1\ m}$)
5. $0.041$ liters (conversion factor: $\frac{1\ L}{1000\ mL}$)