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35. solve for x. triangle with angle 48°, and sides/angles labeled 11x …

Question

  1. solve for x.

triangle with angle 48°, and sides/angles labeled 11x − 5, 9x − 3

Explanation:

Step1: Recall triangle angle sum

The sum of angles in a triangle is \(180^\circ\). So, \(48 + (11x - 5) + (9x - 3) = 180\).

Step2: Simplify the left side

Combine like terms: \(48 - 5 - 3 + 11x + 9x = 180\) → \(40 + 20x = 180\).

Step3: Solve for x

Subtract 40: \(20x = 180 - 40 = 140\). Divide by 20: \(x = \frac{140}{20} = 7\).

Answer:

\(x = 7\)